[leetcode]-268. Missing Number(C语言)

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

Example 1

Input: [3,0,1]
Output: 2

Example 2

Input: [9,6,4,2,3,5,7,0,1]
Output: 8

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

int missingNumber(int* nums, int numsSize) {
    int i,j,k;
    int tem;
    for(i=0;i<numsSize-1;i++)
        for(j=i+1;j<numsSize;j++)
        {
            if(nums[j]<nums[i])
            {
                tem=nums[i];
                nums[i]=nums[j];
                nums[j]=tem;
            }
        }
    if(nums[0]!=0)
        return 0;
    int b=0;
    for(i=1;i<numsSize;i++)
    {
        if(nums[i]==b+1)
        {
            b=nums[i];
            continue;
        }
        else
            break;
    }
    if(i==numsSize)
        return nums[numsSize-1]+1;
    return nums[i]-1;
}

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转载自blog.csdn.net/shen_zhu/article/details/79562037