博弈——poj 2505 A multiplication game

版权声明:低调地前行,越努力越幸运! https://blog.csdn.net/SSYITwin/article/details/83620650

A multiplication game

#include<iostream>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<cstdio>
using namespace std;
int main()
{
	long long n;
	while(~scanf("%lld",&n))
	{
		while(n>18)
		{
			n=ceil(n/18.0);//上取整数
		}
		if(n<=9) cout<<"Stan wins."<<endl;
	    else cout<<"Ollie wins."<<endl;
	}
	
	return 0;
}

猜你喜欢

转载自blog.csdn.net/SSYITwin/article/details/83620650