给定一个字符串 s,找到 s 中最长的回文子串。你可以假设 s 的最大长度为1000。
方案一:
class Solution(object):
def longestPalindrome(self, s):
"""
:type s: str
:rtype: str
"""
n = len(s)
maxl = 0
start = 0
for i in range(n):
if i - maxl >= 1 and s[i-maxl-1: i+1] == s[i-maxl-1: i+1][::-1]:
start = i - maxl - 1
maxl += 2
continue
if i - maxl >= 0 and s[i-maxl: i+1] == s[i-maxl: i+1][::-1]:
start = i - maxl
maxl += 1
return s[start: start + maxl]