PAT 乙级 1028 人口普查

直接利用字符串的大小比较来比较日期的大小

#include <iostream>

using namespace std;

int main(){
    int n;
    cin >> n;

    int count = 0;
    string effeYoung = "2014/09/06", effeOld = "1814/09/06";
    string old, young, oDate = effeYoung, yDate = effeOld;
    string name, date;

    for (int i=0; i<n; i++) {
        cin >> name >> date;
        // 直接利用字符串的大小比较来比较日期的大小
        if (date <= effeYoung && date >= effeOld) {
            count++;
            if (date > yDate){
                young = name;
                yDate = date;
            }
            if (date < oDate) {
                old = name;
                oDate = date;
            }
        }
    }

    cout << count;
    if (count != 0)
        cout << ' ' << old << ' ' << young << endl;

    return 0;
}