POj 1014 Dividing -(DP)

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题目链接：http://poj.org/problem?id=1014
多重背包 –> 01背包。

#include <stdio.h>  
#include <vector>   
#include <algorithm>
using namespace std;

//POJ 1014 Dividing

int main()
{
    int amount;
    int sum, count = 0;
    while (true)
    {
        count++;
        sum = 0;
        vector<pair<int, int> > zero_one_bug;
        for (int i = 0; i < 6; i++) {
            scanf("%d", &amount);
            sum += amount * (i + 1);
            int k = 1;
            while (amount > 0) {
                if (amount < k) {
                    zero_one_bug.push_back(make_pair(amount, amount * (i + 1)));
                    break;
                }
                amount -= k;
                zero_one_bug.push_back(make_pair(k, k * (i + 1)));
                k <<= 1;
            }
        }
        if (sum == 0)break;
        if (sum & 1 == 1)
        {
            printf("Collection #%d:\n", count);
            printf("Can't be divided.\n\n");
            continue;
        }
        int V = sum >> 1; // 价值即容量
        vector<int> F(V + 1); // F[i, v] 表示前i个物品在容量为v的情况下的最大容量。
        for (int i = 0; i < V + 1; i++)
            F[i] = 0;
        const int size = zero_one_bug.size();
        for (int i = 0; i < size; i++)
        {
            int value = zero_one_bug[i].second;
            for (int v = V; v >= value; v--) {
                F[v] = max(F[v], F[v - value] + value);
            }
        }
        printf("Collection #%d:\n", count);
        if (F[V] != V) printf("Can't be divided.\n\n");
        else printf("Can be divided.\n\n");
    }
    system("pause");
    return 0;
}