猿辅导2019校园招聘研发岗位在线笔试编程题-2018.08.26

版权声明:本人ZZU在校学生,文章均为个人心得,有不足之处请不吝赐教! https://blog.csdn.net/whl_program/article/details/82086361

1-1
1-2.jpg
1-3.jpg

#include <iostream>
#include <vector>
using namespace std;

int main()
{
    int memberCount, carCount;
    cin >> memberCount >> carCount;
    int* members = new int[memberCount];
    for(int i=0; i<memberCount; i++){
        cin >> members[i];
    }
    vector<int> res;
    int remainder = memberCount%carCount;//余数
    int business = memberCount/carCount;//商 出去余数外剩余区间个数
    if(remainder){//最后面的区间加入数组
        for(int i=0; i<remainder; i++)
            res.push_back(members[business*carCount+i]);
    }
    memberCount -= remainder;
    for(int i=business-1; i>=0; i--){//区间从后往前依次加入数组
        for(int j=0; j<carCount; j++){
            res.push_back(members[carCount*i+j]);
        }
    }
    if(!res.size())
        return 0;
    for(int i=0; i<res.size()-1; i++)
        cout << res[i] << " ";
    cout << res[res.size()-1] << endl;
    delete[] members;
    return 0;
}
/*
5 3
1 3 5 2 4

9 3
1 2 3 4 5 6 7 8 9

2 3
1 2
*/

2-1.jpg
2-2.jpg
2-3
2-4
2-5.jpg

#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
int N;
int main()
{
    scanf("%d\n", &N);
    int k = N/3;
    string str;
    getline(cin, str);
    int temp = 2*k-1;//上半部分两个字符间的空格个数
    //输出Y的上半部分
    for(int i=0; i<k; i++){
        for(int j=0; j<i; j++)//输出前面空格
            printf(" ");
        printf("%c", str[2*i]);
        for(int q=0; q<temp; q++){//输出中间空格
            printf(" ");
        }
        temp -= 2;
        printf("%c\n", str[2*i+1]);
    }
    //输出Y的下半部分
    for(int i=0; i<=k; i++){
        for(int j=0; j<k; j++)
            printf(" ");
        printf("%c\n", str[2*k+i]);
    }
    return 0;
}
/*
4
a3f/

7
abcdefg

10
iiiiiiiiii
*/

猜你喜欢

转载自blog.csdn.net/whl_program/article/details/82086361