Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3
Sample Output
19
18
10
-17
-14
-4
代码：
#include <stdio.h>
int main()
{
int t,n;
char ch;
scanf("%d",&t);
getchar();
while(t--)
{
scanf("%c%d",&ch,&n);
getchar();
if(ch>='A'&&ch<='Z')
printf("%d\n",n+ch-'A'+1);
else
printf("%d\n",n-(ch-'a'+1));
}
return 0;
}