Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6 R 1 P 2 G 3 r 1 p 2 g 3
Sample Output
19 18 10 -17 -14 -4
#include<stdio.h> #include<string.h> int main() { int t; scanf("%d",&t); getchar(); char a; int b,answer; while(t--) { answer=0; scanf("%c%d",&a,&b); getchar(); if(a>='a'&&a<='z') answer=-1*((int)a-96); else if(a>='A'&&a<='Z') answer=(int)a-64; printf("%d\n",answer+b); } return 0; }