HDU 2123 An easy problem

#include <iostream>
using namespace std;
int main()
{
	int n,m,i,j,k,a[233][233];
	cin>>n;
	while(n--){
		cin>>m;
		for(i=1;i<=m;i++)
		for(j=1;j<=m;j++){
			cout<<i*j;
			if(j<m) cout<<' ';
			if(j==m) cout<<endl;
		}
	}
	return 0;
}

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转载自blog.csdn.net/janilina/article/details/80573890