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【编程题】约瑟夫环问题
代码1,非递归
class Solution {
public:
int LastRemaining_Solution(int n, int m)
{
if(n==0) return -1;
int s=0;
for(int i=2;i<=n;i++){
s=(s+m)%i;
}
return s;
}
};
代码2,递归
class Solution {
public:
int LastRemaining_Solution(unsigned int n, unsigned int m)
{
if(n==0)
return -1;
if(n==1)
return 0;
else
return (LastRemaining_Solution(n-1,m)+m)%n;
}
};