1002 A + B Problem II 大正整数

 注意这个输出格式，最后一个case后面不应该有空格

Poblem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

#include<iostream>
#include<string>
#include<cstring>//memset函数头文件
//#include<cstdio>//输出格式用printf方便
using namespace std;
//用数组来存放大正整数
struct bign{
   int d[2000];
   int len;
   bign(){//结构体初始化
       memset(d,0,sizeof(d));
       len=0;
   }
};
//将字符串转换为bign
bign change(string x){
    bign a;
    a.len=x.length();
    for(int i=0;i<x.length();i++)
        a.d[i]=x[x.length()-i-1]-'0';
    return a;
}
//相加
bign add(bign a,bign b){
    bign c;
    int carry=0,temp;
    for(int i=0;i<a.len||i<b.len;i++){
        temp=a.d[i]+b.d[i]+carry;
        c.d[i]=temp%10;
        carry=temp/10;
        c.len++;
    }
    if(carry!=0){
        c.d[c.len++]=carry;
    }
    return c;
}

int main()
{
    int n;
    cin>>n;
    string a,b;
    for(int i=1;i<=n;i++){
        cin>>a>>b;
        bign ans=add(change(a),change(b));
        //printf("Case %d:\n",i);
        cout<<"Case "<<i<<":"<<endl;
        //printf("%s + %s = ",a,b);  //csdio没有字符串类型，%s只能用于字符串数组
        cout<<a<<" + "<<b<<" = ";
        for(int i=ans.len-1;i>=0;i--)
            cout<<ans.d[i];
        cout<<endl;//cout<<endl<<endl; 最后一个case后面不能有空格
        if(i!=n) cout<<endl;
    }
    return 0;
}