Problem Description
The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.
For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.Input
The input file will contain a list of positive integers, one per line. The end of the input will be indicated by an integer value of zero.
Output
For each integer in the input, output its digital root on a separate line of the output.
Sample Input
24
39
0
Sample Output
6
3
嗯。。本来想用字符串的，担心字符串不够大，结果看到大佬们都是一个一个当做字符处理的
没考虑全面，找bug找了好久，附上ac代码；
#include <iostream>
using namespace std;
int main()
{
int sum=0;
char a;
while(a=getchar())
{
if(a=='\n')
{
if(sum==0) break;
else if(sum%9==0) sum=9;
else sum%=9;
cout<<sum<<endl;
sum=0;
}
if(a!='\n') sum+=a-'0';//if必须要有，不然每次输出之后都会加上'\n'
}
return 0;
}