自底向上的归并排序

自底向上的归并排序和自顶向下的归并排序差不多,基本思想都是利用分治。需要注意的是管理好每次排序的lo,mid.hi的值
具体实现:

public class Merge{
    private Comparable[] aux;
    //排序
    public static void sort(Comparable[] a){
        aux = new Comparable[a.length];
        for(int sz=1;sz<N;sz+=sz){ //sz为每次归并的子串长度
            for(int lo=0;lo<N;lo+=sz+sz){
                merge(a,lo,lo+sz-1,Math.min(N-1,lo+sz+sz-1);
            }
        }
    }
    //归并两个数组
    private static void merge(Comparable [] a,int lo,int mid,int hi){
        for(int i=lo;i<=hi;i++)
            aux[i]=a[i];
        int j=lo;
        int k = mid+1;
        for(int i=lo,i<=hi;i++){
            if(j>mid) a[i] = aux[k++];
            else if(k>hi) a[i] = aux[j++];
            else if(less(a[j],a[k])) a[i] = aux[j++];
            else a[i] = aux[k++];
        }
    }
    //判断q是否小于p
    private static boolean less(Comparable q,Comparable p) {
        return q.compareTo(p)<0;
    }
    //展示数组
    public static void show(Comparable[] a) {
        for(int i=0;i<a.length;i++) {
            System.out.print(a[i]+" ");
        }
        System.out.println();
    }
    //判断数组是否有序
    public static boolean isSorted(Comparable[] a) {
        for(int i =1;i<a.length;i++) {
            if(less(a[i],a[i-1])) {
                return false;
            }
        }
        return true;
    }
    //测试
    public static void main(String[] args) {
        Integer[] a = {5,2,9,8,6,3,0,15,25,46,10,1,9,4,7};
        sort(a);
        assert isSorted(a);
        show(a);
    }
}

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转载自blog.csdn.net/qq_37520037/article/details/81606727
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