A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 410313 Accepted Submission(s): 79511
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
21 2112233445566778899 998877665544332211
Sample Output
Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110
处理大数问题一般用java会很简单
这题需要注意的是输出格式，在输出最后一个测试数据结果时，不再输出空白行！！
AC代码（java）：
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
for(int i=1;i<=t;i++)
{
BigInteger a=sc.nextBigInteger();
BigInteger b=sc.nextBigInteger();
System.out.println("Case "+i+":");
if(i<t)
{
System.out.println(a+" + "+b+" = "+a.add(b));
System.out.println();
}
else
System.out.println(a+" + "+b+" = "+a.add(b));
}
}
}同时，ACM中提交Java代码的规范格式：
多行输入时的代码格式：
Scanner sc= new Scanner(System.in);
while(sc.hasNext()){
......
} 类名：
public class Main {
}