PTA The Missing Number (20分)

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Given N integers, you are supposed to find the smallest positive integer that is NOT in the given list.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤10​5​​). Then N integers are given in the next line, separated by spaces. All the numbers are in the range of int.

Output Specification:

Print in a line the smallest positive integer that is missing from the input list.

Sample Input:

10
5 -25 9 6 1 3 4 2 5 17

Sample Output:

7
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <stack>
#include <queue>
#include <set>
#include <map>
#include <vector>
#include <ctime>
#include <cctype>
#include <bitset>
#include <utility>
#include <sstream>
#include <complex>
#include <iomanip>
#include<climits>//INT_MAX
//#include<bits/stdc++.h>
#define PP pair<ll,int>
#define inf 0x3f3f3f3f
#define llinf 0x3f3f3f3f3f3f3f3fll
#define dinf 1000000000000.0
#define PI 3.1415926
typedef long long ll;
using namespace std;
int const mod=1e9+7;
const int maxn=1000100;
bool fg[maxn]={false};
int n,num;
int main(){
    scanf("%d",&n);
    for(int i=0; i<n; i++){
        scanf("%d",&num);
        if(num>0&&num<maxn)
            fg[num]=true;
    }
    for(int i=1; i<maxn; i++){
        if(fg[i]==false){
            printf("%d",i);
            return 0;
        }
    }
    return 0;
}

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转载自blog.csdn.net/weixin_44170305/article/details/108526620