python求数组标准差
L=[101,25,38,29,108,121]
b=0
sum1=0
pj=sum(L)/len(L);
for a in range(len(L)):
b=(L[a]-pj)**2
sum1 = b+sum1
print("L的标准差为：",(sum1/len(L))**0.5)
python求数组标准差
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转载自blog.csdn.net/weixin_44220805/article/details/105306239
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