大疆创新 2020校招 软件类岗位A卷 应该吃哪个呢（多重背包问题）

      这道题是一个多重背包问题，将其转化为01背包后既可以解出。

#include <iostream>
#include<iomanip>
#define INF (0x3f3f3f3f)

using namespace std;

int Price[2001], Manyi[2001];		//100*20
int Data[2001][10001];

int main()
{

	int N, T;
	while (cin >> N >> T)		//代表有输入
	{
		memset(Price, 0, sizeof(Price));
		memset(Manyi, 0, sizeof(Manyi));

		int count = 1;
		for (int i = 0; i < N; i++)
		{
			int price, manyi, number;
			int j = 0;
			cin >> price >> manyi >> number;
			while (number >= pow(2, j))		//将多重背包转化为01背包
			{
				Price[count] = pow(2, j) * price;
				Manyi[count] = pow(2, j) *manyi;
				number -= pow(2, j);
				count++;
				j++;
			}
			for (; j >= 0; j--)
			{
				if (number >= pow(2, j))
				{
					Price[count] = pow(2, j) * price;
					Manyi[count] = pow(2, j) *manyi;
					number -= pow(2, j);
					count++;
				}
				//else if (number == 0)
				//	break;
			}
			//cout << count << endl;
		}
		for (int i = 1; i <= count; i++)
		{
			for (int j = 1; j <= T; j++)
			{
				if (j >= Price[i])
					Data[i][j] = max(Data[i - 1][j], Data[i - 1][j - Price[i]] + Manyi[i]);
				else
					Data[i][j] = Data[i - 1][j];
			}
		}
		cout << Data[count][T] << endl;
		
	}

	/*Solution SO;
	SO.longestDecomposition(a);*/
	return 0;
}