规律如下:
找规律
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=1e6+10;
ll a[N];
int n,m;
int main(){
while(~scanf("%d",&n)){
for (int i = 1; i <= 2*n-1; ++i) {
scanf("%lld",&a[i]);
}
ll ans=0;
scanf("%d",&m);
for (int i = 1,x,y,t=0; i <= m; ++i) {
scanf("%d%d",&x,&y);
x=(x+t)%n;
y=(y+t)%n;
ll res=0;
for (int j = 1; j <= n; ++j) {
res+=a[n-x+j-1]*a[n+y-j+1];
}
t=res;
ans+=res;
}
cout<<ans<<endl;
}
return 0;
}