[蓝桥杯]约数倍数选卡片dfs

 

 http://oj.ecustacm.cn/problem.php?id=1450

#include<bits/stdc++.h>
#define ls o<<1
#define rs o<<1|1
#define MS(x,y) memset(x,y,sizeof(x))
#define MC(x,y) memcpy(x,y,sizeof(x))
typedef long long LL; 
template<class T> inline void gmax(T &a,T b){if(b>a)a=b;}
template<class T> inline void gmin(T &a,T b){if(b<a)a=b;}
const int N=105,M=0,Z=1e9+7,W=13,L=2e6;
const double eps=1e-10;
const int dy[4]={-1,0,0,1},dx[4]={0,-1,1,0};
using namespace std;
int casenum,casei;
int id;
int n,m;
int num[N];
vector<int> a[N],b;
//vector<int> si; 
int dfs(int x){
	for(int i=a[x].size()-1;i>=0;i--){
		int u=a[x][i];
		if(num[u]){
			num[u]--;
			int t=dfs(u);//now I take the u
			num[u]++;
			if(t==-1){
				return 1;
			}
		}
	}
	return -1;// the first time to call this dfs
}
int main(){
//	freopen("in.txt","r",stdin);
	string s;
	getline(cin,s);
	stringstream in1(s);
	int x;
	int mmax=-0x3f3f3f3f;
	int mmin=0x3f3f3f3f;
	while(in1>>x){
		num[x]++;
		gmax(mmax,x);
		gmin(mmin,x);
	}
	getline(cin,s);
	stringstream in2(s);
	while(in2>>x){
		b.push_back(x);
	}
	for(int i=mmin;i<=mmax;i++){
		if(num[i]){
			num[i]--;
			for(int j=mmin;j<=mmax;j++){
				if(num[j]){
					if(i%j==0||j%i==0){
							a[i].push_back(j);
						}
					}
				}
				num[i]++;//related numbers
		}
	}
	sort(b.begin(),b.end());
	for(int i=0;i<b.size();i++){
		num[b[i]]--;
		int t=dfs(b[i]);
		if(t==-1){
			printf("%d\n",b[i]);return 0;
		}
		num[b[i]]++;
	}
	puts("-1");
	return 0;
}

 1.优先用大数,会提前结束游戏

2.类似枚举的dfs

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转载自blog.csdn.net/ujn20161222/article/details/104003666