[LeetCode 解题报告]136. Single Number

Given a non-empty array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Example 1:

Input: [2,2,1]
Output: 1

Example 2:

Input: [4,1,2,1,2]
Output: 4
class Solution {
public:
    int singleNumber(vector<int>& nums) {
        int res = 0;
        for (int i = 0; i < nums.size(); i ++)
            res = res ^ nums[i];
        return res;
    }
};
发布了401 篇原创文章 · 获赞 39 · 访问量 45万+

猜你喜欢

转载自blog.csdn.net/caicaiatnbu/article/details/103823773
今日推荐