[leetcode]136. Single Number

链接:https://leetcode.com/problems/single-number/description/

Given a non-empty array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Example 1:

Input: [2,2,1]
Output: 1

Example 2:

Input: [4,1,2,1,2]
Output: 4
class Solution{
public:
    int singleNumber(vector<int>& nums){
        int len=nums.size();
        int temp=0;
        for(int i=0;i<len;i++)
           temp=temp^nums[i];
        return temp;

   }
};

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转载自blog.csdn.net/xiaocong1990/article/details/82286739
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