1078 Hashing (25分)

The task of this problem is simple: insert a sequence of distinct positive integers into a hash table, and output the positions of the input numbers. The hash function is defined to be ( where TSize is the maximum size of the hash table. Quadratic probing (with positive increments only) is used to solve the collisions.

Note that the table size is better to be prime. If the maximum size given by the user is not prime, you must re-define the table size to be the smallest prime number which is larger than the size given by the user.

Input Specification:

Each input file contains one test case. For each case, the first line contains two positive numbers: MSize (≤) and N (≤) which are the user-defined table size and the number of input numbers, respectively. Then N distinct positive integers are given in the next line. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the corresponding positions (index starts from 0) of the input numbers in one line. All the numbers in a line are separated by a space, and there must be no extra space at the end of the line. In case it is impossible to insert the number, print "-" instead.

Sample Input:

4 4
10 6 4 15

Sample Output:

0 1 4 -


  1 #define _CRT_SECURE_NO_WARNINGS  
  2 #include<stdio.h>
  3 #include<malloc.h>
  4 #include<math.h>
  5 #define MAXTABLESIZE 20000
  6 
  7 typedef int ElementType;
  8 typedef enum { Legitimate, Empty, Deleted } EntryType;
  9 typedef struct HashEntry Cell;
 10 struct HashEntry
 11 {
 12     ElementType Data;
 13     EntryType Info;
 14 };
 15 
 16 typedef struct HblNode* HashTable;
 17 struct  HblNode
 18 {
 19     int TableSize;
 20     Cell* Cells;
 21 };
 22 
 23 int NextPrime(int N)
 24 {
 25     if (N == 1)
 26         return 2;
 27     int p = (N % 2) ? N + 2 : N + 1;
 28     int i;
 29     while (p<=MAXTABLESIZE)
 30     {
 31         for (i = (int)sqrt(p); i > 2; i--)
 32             if (p % i == 0)
 33                 break;
 34         if (i == 2)break;
 35         else
 36             p += 2;
 37     }
 38     return p;
 39 }
 40 int Hash(int Key, int TableSize)
 41 {
 42     return Key % TableSize;
 43 }
 44 HashTable CreateHashTable(int TableSize)
 45 {
 46     HashTable H;
 47     H = (HashTable)malloc(sizeof(struct HblNode));
 48     H->TableSize = NextPrime(TableSize);
 49     H->Cells = (Cell*)malloc(H->TableSize * sizeof(Cell));
 50     for (int i = 0; i < H->TableSize; i++)
 51         H->Cells[i].Info = Empty;
 52     return H;
 53 }
 54 
 55 int Find(HashTable H, ElementType Key)
 56 {
 57     int NewPos, CurPos;
 58     int CNum = 0;
 59     NewPos = CurPos = Hash(Key, H->TableSize);
 60     while (H->Cells[NewPos].Info!=Empty&&H->Cells[NewPos].Data!=Key)
 61     {
 62         ++CNum;
 63         int Flag = 0;
 64         NewPos = CurPos+CNum * CNum;
 65         if (CNum>=H->TableSize)
 66             return -1;
 67         while (NewPos >= H->TableSize)
 68             NewPos -= H->TableSize;
 69     }
 70     return NewPos;
 71 }
 72 
 73 int Insert(HashTable H, ElementType Key)
 74 {
 75     int Pos = Find(H, Key);
 76     if (Pos ==-1)
 77         return -1;
 78     if (H->Cells[Pos].Info != Legitimate)
 79     {
 80         H->Cells[Pos].Data = Key;
 81         H->Cells[Pos].Info = Legitimate;
 82     }
 83     return Pos;
 84 }
 85 
 86 int main()
 87 {
 88     int M, N;
 89     scanf("%d %d", &M, &N);
 90     HashTable H = CreateHashTable(M);
 91     int i;
 92     for (i = 0; i < N-1; i++)
 93     {
 94         int num;
 95         scanf("%d", &num);
 96         int Pos = Insert(H,num);
 97         if (Pos != -1)
 98             printf("%d ", Pos);
 99         else
100             printf("- ");
101     }
102     int num;
103     scanf("%d", &num);
104     int Pos = Insert(H, num);
105     if (Pos != -1)
106         printf("%d", Pos);
107     else
108         printf("-");
109     return 0;
110 }
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转载自www.cnblogs.com/57one/p/12071432.html