版权声明:本文为博主原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接和本声明。
上一篇eclipse搭建maven web项目这里实现简单的servlet传参小Demo,项目结构:
1.pom.xml文件加入servlet包
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.citywy</groupId>
<artifactId>mytest02</artifactId>
<packaging>war</packaging>
<version>0.0.1-SNAPSHOT</version>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<!-- 添加servlet -->
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>servlet-api</artifactId>
<version>2.5</version>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<finalName>mytest02</finalName>
</build>
</project>
2.UserServlet.java
package com.citywy.servlet;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class UserServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public UserServlet() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
request.setCharacterEncoding("utf-8");
response.setContentType("text/html;charset=utf-8");
String name=request.getParameter("uname");
String pwd=request.getParameter("upwd");
System.out.println("输出"+name+"--"+pwd);
request.setAttribute("someinfo", "这是登陆成功提示信息!");
request.getRequestDispatcher("index.jsp").forward(request, response);
}
}
3.web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<description></description>
<display-name>UserServlet</display-name>
<servlet-name>UserServlet</servlet-name>
<servlet-class>com.citywy.servlet.UserServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>UserServlet</servlet-name>
<url-pattern>/UserServlet</url-pattern>
</servlet-mapping>
</web-app>
4.index.jsp
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">
<title>User Login</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>
<body>
<div>
<h1>用户登录</h1>
<!-- action应该这么写,/web应用名称/servlet的url -->
<form action="/mytest02/UserServlet" method="post">
用户名:<input type="text" name="uname"/><br/>
密 码:<input type="password" name="upwd"/><br/>
<input type="submit" class="btn btn-primary" value="登录"/>
<input type="button" class="btn btn-primary" value="取消"/>
${someinfo }
</form>
</div>
</body>
</html>
运行效果如图:
TIP:在Tomcat中运行时出现了无法加载到wtpwebapps或webapps下的情况,解决方案是servers下右击clean:将原先编译到tomcat服务器上的程序,先清除掉,然后再重新编译。