c Switch Game开关游戏

Problem Description
There are many lamps in a line. All of them are off at first. A series of operations are carried out on these lamps. On the i-th operation, the lamps whose numbers are the multiple of i change the condition ( on to off and off to on ).

Input
Each test case contains only a number n ( 0< n<= 10^5) in a line.

Output
Output the condition of the n-th lamp after infinity operations ( 0 - off, 1 - on ).

Sample Input
1
5

Sample Output
1
0

Hint
hint

Consider the second test case:

The initial condition : 0 0 0 0 0 …
After the first operation : 1 1 1 1 1 …
After the second operation : 1 0 1 0 1 …
After the third operation : 1 0 0 0 1 …
After the fourth operation : 1 0 0 1 1 …
After the fifth operation : 1 0 0 1 0 …

The later operations cannot change the condition of the fifth lamp any more. So the answer is 0.

#include<stdio.h>
void main()
{
    int n,i,swi;
    while(~scanf("%d",&n))
    {
		swi = 0;
        for(i=1;i<=n;i++){
			if(n%i==0){
				if(swi==0){
				    swi++;
				}else{
				    swi--;
				}
			}
		}
		printf("%d\n",swi);
    }
}