15 二分查找

15 二分查找


# 二分查找 a必须是有序数组

# 非递归
def binary_search(a, item):

	n = len(a)

	head = 0
	rear = n - 1

	while head <= rear:
		mid = (head + rear) // 2

		if a[mid] == item:
			return mid

		elif a[mid] < item:
			head = mid + 1

		else:
			rear = mid - 1

	return -1


# 递归
def binary_search(a, head, rear, item):

	if head > rear:
		return -1

	mid = (head + rear) // 2

	if a[mid] == item:
		return mid

	elif a[mid] < item:
		return binary_search(a, mid + 1, rear, item)

	else:
		return binary_search(a, head, mid - 1, item)



if __name__ == '__main__':
	a = [0, 1, 2, 4, 6, 8, 10, 17, 30]

	print(binary_search(a, 2))

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转载自blog.csdn.net/qq_41089707/article/details/89301702