Programming Assignment2 - Deque and Randomized Queues Review
课程笔记
Subtext: Modular Programming
- Stacks and Queues are fundamental data types
- Value: collection of objects
- Basic Operation: insert, remove, iterate.
- Difference: which item do we move? -> Stack: LIFO(last in first out) Queue: FIFO(first in first out)
- Client, implementation, interface
- Client: program using operations defined in interface
- Implementation: actual code implementing operations
- Interface: description of data type, basic operations
Stack Programming API:
public class StackOfStrings
StackOfStrings() //create an empty stack
void push(String item) //insert a new string onto stack
String pop() //remove and return the string most recently added
boolean isEmpty() //is the stack empty?
linked-list implementation
//Attention: Stack have only one exit -> only one pointer is enough
/*Corner Cases:
client add a null item -> IllegalArgumentException
remove() from empty stack -> NoSuchElementException
*/
public class StackOfStrings {
private Node first;
private class Node {
String item;
Node next;
}
public boolean isEmpty() {
return first == null;
}
public StackOfStrings {
Node first = null;
}
public void push(String item) {
//Improve: add exception to deal with
Node oldfirst = first;
first = new Node(); //Attention: must craete a new instance here
first.item = item;
first.next = oldfirst;
}
public String pop() {
String item = first.item;
first = first.next;
return item;
}
需要完成一种角色的转换,当你在实现一个API的时候,需要考虑的是
* 实现某个方法所要使用的数据结构,
* 调用方法 or 自己写方法,
* API的性能要求 -> 使用哪种算法可以满足要求 查找,插入,删除 时间 + 空间
Stack API
Stack的链表实现
Stack的数组实现(resize array)
Queue的链表实现
Queue的数组实现(resize array)
对于双向队列的理解有误,导致错误实现。
双向对别不应当是两个队列的水平叠加,见figure 1
作业总结:
1.对于文件的读写基本操作命令不够熟悉
2.对于问题的定义 出现了没有搞清楚题目要求的现象,包括Deque的基本操作 以及Permutation 类当中,应当是读取全部数据,输出k个数据,而不是读取k个数据,输出全部数据的问题