【算法设计与分析作业题】第五周:11. Container With Most Water

题目

C++ solution

class Solution {
public:
    int maxArea(vector<int>& height) {
        int len = height.size();
        int max_area = 0;
        for (int i = 0; i < len - 1; ++i)
        {
        	for (int j = i + 1; j < len; ++j)
        	{
        		int small = height[i] < height[j] ? height[i] : height[j];
        		int area = small * (j - i);
        		if (area > max_area)
        		{
        			max_area = area;
        		}
        	}
        }
        return max_area;
    }
};

简要题解

采用暴力解题法,直接遍历任意两条垂直线组成的容器,找出这些容器的容量的最大值。

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转载自blog.csdn.net/For_course/article/details/82966650