51 nod 1101 换零钱

 1 #include <iostream>
 2 using namespace std;
 3 #define mod 1000000007
 4 int dp[100005];
 5 
 6 int main()
 7 {
 8     int a[]={1,2,5,10,20,50,100,200,500,1000,2000,5000,10000};
 9     int n;
10     cin>>n;
11     dp[0] = 1;
12     for (int i=0;i<13;i++)
13     {
14         for (int j=a[i];j<=n;j++)
15             dp[j] = (dp[j]+dp[j-a[i]])%mod;
16     }
17     cout<<dp[n]<<endl;
18 }

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