Problem Description
This is Kolakosiki sequence:
1,2,2,1,1,2,1,2,2,1,2,2,1,1,2,1,1,2,2,1……. This sequence consists of
1 and
2, and its first term equals
1. Besides, if you see adjacent and equal terms as one group, you will get
1,22,11,2,1,22,1,22,11,2,11,22,1……. Count number of terms in every group, you will get the sequence itself. Now, the sequence can be uniquely determined. Please tell HazelFan its
nth element.
Input
The first line contains a positive integer
T(1≤T≤5), denoting the number of test cases.
For each test case:
A single line contains a positive integer n(1≤n≤107).
For each test case:
A single line contains a positive integer n(1≤n≤107).
Output
For each test case:
A single line contains a nonnegative integer, denoting the answer.
A single line contains a nonnegative integer, denoting the answer.
Sample Input
2 1 2
Sample Output
1 2
分析:
这是一个名叫Kolakoski的序列(
https://baike.baidu.com/item/Kolakoski%E5%BA%8F%E5%88%97/16683856?fr=aladdin)
按照规律打表,直接输出即可。
- #include<bits/stdc++.h>
- using namespace std;
- int a[10000005];
- int f[5];
- int main()
- {
- int t,sum=1,k=2,z=2,n;
- cin>>t;
- a[1]=1;a[2]=2;
- for(long long i=3;i<=10000005;i++)
- {
- sum++;
- a[i]=z;
- if(sum==a[k])
- {
- sum=0;k++;
- if(z==2) z=1;
- else z=2;
- }
- }
- while(t--)
- {
- cin>>n;
- cout<<a[n]<<endl;
- }
- }