A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?
Above is a 7 x 3 grid. How many possible unique paths are there?
Note: m and n will be at most 100.
Example 1:
Input: m = 3, n = 2 Output: 3 Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner: 1. Right -> Right -> Down 2. Right -> Down -> Right 3. Down -> Right -> Right
Example 2:
Input: m = 7, n = 3 Output: 28
方法一:(碰到这种问题,直接解答无法解答,直接利用动态规划)
class Solution {
public int uniquePaths(int m, int n) {
if(n==0||m==0){
return 0;
}
if(m==1||n==1){
return 1;
}
int [][] dp=new int[m+1][n+1];
for(int i=0;i<=m;i++){
dp[i][0]=1;
}
for(int j=0;j<=n;j++){
dp[0][j]=1;
}
for(int i=1;i<=m;i++){
for(int j=1;j<=n;j++){
dp[i][j]=dp[i-1][j]+dp[i][j-1];
}
}
return dp[m-1][n-1];
}
}
时间复杂度:O(n^2)
空间复杂度:O(n)