One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that’s why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that’s why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.
Input
The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.
Output
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.
Examples
Input
8
Output
YES
Note
For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).
问题链接：https://vjudge.net/problem/CodeForces-4A
问题简述：皮特和比利两个人分西瓜，两个人都喜欢偶数斤的量，输入一个西瓜斤数，判断它能否被分为两个偶数，如果可以输出YES，不行输出NO
问题分析：首先判断是不是为2（除2以外的偶数都能分为两个偶数），在判断他是不是为偶数，以及这个数减2是不是为偶数即可。
AC通过的C++语言程序如下：
#include<iostream>
using namespace std;
int main()
{
int w;
cin >> w;
if (w == 2) { cout << "NO"; }
else
{
if (w % 2 == 0) { cout << "YES"; }
else
{
if ((w - 2) % 2 == 0) { cout << "YES"; }
else { cout << "NO"; }
}
}
return 0;
}