矩阵求导与转置运算

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线性代数补充


前言:在推导算法过程中遇到一些数学运算,遇到了就记录下,方便回忆


矩阵转置

( A + B ) T = A T + B T ( A B ) T = B T A T (A+B)^T = A^T+B^T \\ (AB)^T = B^TA^T

矩阵求导

A x x = A T A x x T = A x T A x = A \frac{\partial Ax}{\partial x} = A^T \\ \frac{\partial Ax}{\partial x^T} = A \\ \frac{\partial x^TA}{\partial x} = A \\
x T A x x = ( A T + A ) x \frac{\partial x^TAx}{\partial x} = (A^T+A)x 若A是对称矩阵,即A^T = A,则:
x T A x x = 2 A x \frac{\partial x^TAx}{\partial x} = 2Ax


参考:
向量,标量对向量求导数

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转载自blog.csdn.net/KevinBetterQ/article/details/83214193