1737棋牌源码 精品,八数码游戏（启发式搜索A算法）

    8位数字谜3×3九宫棋盘，把1-8个棋盘的数量，剩余的空间，只能通过移动棋盘到空间来改变棋盘的布局。问题解决了——给定初始布局（即初始状态）和目标布局（即目标布局）。状态）如何将棋盘从初始布局移动到目标布局解决方案路径——是使用广度优先搜索方法解决问题的合法步骤序列：建立用于表示问题state的数据结构3×3、*矩阵元素的矩阵S ij{0，1，...8}；其中1小于I，j小于3，*0表示空白空间，数字1-8表示对应的棋牌。初始状态S0:23目标状态Sg:123 1 8 4 0 4 0 7 7 6 5形成操作符集：*直观方法——为每个棋牌开发一组棋牌可能的移动：左、上、右、下四种移动。这需要32个操作符。*简单的方法——只对空间进行这四个步骤，因为只有靠近空间的棋牌才能移动。*空间移动的唯一限制是它不能从che中移出。应用************************************************************************************************************************************************************************评估函数：f(n)=D(n)+W(n)，其中：D(n)是n的深度n，w(n)不在位，然后w(n)<h*(n)。n)满足A*算法的约束条件。编程注意：1：前驱节点的深度和记录。队列队列首部和队列尾部元素的函数。（2）采用宽度优先搜索，然后从打开的表格中选择相对函数值最小的节点。注意，深度优先搜索不适合于在完全没有解决方案之前可以选择的分支。3：递归算法应用程序*/以下是代码：includelt;iostreamgt;includelt;cstdlibgt;使用名称空间std;int sum=0定义N 1000；int＝0，步长＝0；int m＝0，ta＝0；int ZuiHui{n}；chdicdir { 4 }＝{u，r，d，l }；///方向对应于字母chpopcdir {4 }＝{d，l，u，r}；//反向对应于字母const int状态{9 }＝{1,2，3，8，0，4，7，6，5}； / /目标状态const int imaLoC {9 }} { 4，0，1，2，5，8，7，6，3 }；//basHUMA {int cCt{{}；int a；char fx；int cIn；int PRINT；int Pin int；int HuchSU}；内联int {返回AGT；0a:-a；//绝对值函数}（int {ININLINE，INT{Read 1 }洛赫{{返回} } LOC ReRANSTABS（LOC1 /3-LOC2）3）+ABS（LoC1%3-LoC2 % 3）；//列和行之间的差值之和是它们的目标位置和估计值的距离} INTINT INT（INT状态{ 9 }）//它们的目标位置和估计值{INTANS＝0；（int i＝0；ILT；9；I+）IF（状态{I}）。ans+=Manh(i，._loc state{i}{state}内联bool canMove(int loc，int dir，int nxt)/确定空间在LOC位置时是否可以移动到dir，同时在LOC位置时返回到移动位置NXT{.(dir){case}。Er返回LOGTT＝LOC-3；2；案例1：NXT= LOC + 1；案例1：NXT= LOC+1；案例1：NXT= LOC+1；右返回LOC% 3！= 2; case 2: NXT = LOC LOC + 3; return loclt; 6; / / / / / / / / / lower case 3: NXT = loc-1: NXT = LOC NXT = LOC loc-1; return LOC loc% 3; / / / / / / left}}}}}}}}}}}}}}}} bashumbashuma chuchuchuchuchuchuchuhua (bashuma bsm{{{{{9} ={{{2, 8, 8, 8, chushihua {9} = {3,1,8,7,6,4,0,2,5};// / / 21 steps // / / / / / / / / / / / / / / / 21 steps / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / 9} = {1, 3, 4, 7, 8, 0, 6, 5, 2}; the // can be tested for (k = 0 using the different initial states above;Klt; 9; K + + {bsm {0}} {bsm {0}}} {k}}} = bsmchushihua {k}}}; Bsm {0}}}}bsm {0}} {a = a = h (bsm {0}}}}}}} {a = ccstate}; Bsm {0}} {0}} {fx = 0; Bsm {0} {0}} {0}} {0}} {flag} = 1; Bsm {0}} {0}; BSM { 0 } { 0 } { 0 } { 0 } }}}}}}{fx＝0；bsm { 0；bsm {0 }{0 }}}{旗子＝1；bsm {0 }；bsm {0 }{0 }；bsm {+）bsm 1 {t}}。CcStA{K}= BSM{{ }}。CcSTATA{K}；}//BSM1{TA}。a = h(bsm {head}.Ccstate) + head; BSM1 {ta}} {ta}}} {bsm1} {ta}}}}} {ta}}}} {bsm1} {ta}}} {ta}}}} {flag}} {ta}}} {flag} = 0; if (m = = = = = = = = = = = = = = = = = = = - 1; BSM1 {ta}} {ta}} {pre = Zuixiao {m-1}}}}} {m-pre = Zuixiao {m-1}};}else {{{{BSM1 {ta}}}}}}else {bsmsm1 {ta}}}}}}{{pre = ZuixiAO{PRE=最晓{M-1 } {头}。CSTATM；BSM1 {TA}。曾舒= BSM1 {BSM1 {TA}。预}。曾舒+ 1；/*PrtTf（
）%d，ta）；（k＝0；KLT；9；k++）{if（k% 3＝＝0）PrtTf（））PrdTf（%d，BSM1 {Ta}.CSTATE {K}）；}PrTNF（,ta-1);*/ } void rudui(bashuma bsm{},bashuma bsm1{},int i) { head++; int k; for(k=0;klt;9;k++) { bsm{head}.ccstate{k}=bsm1{i}.ccstate{k}; } bsm{head}.a=bsm1{i}.a; bsm{head}.fx=bsm1{i}.fx; bsm{head}.pre=i;//*printf (% d, head); for (k = 0; K lt; 9; K + + +) {if (k% 3 = = = 0) printf (% 3 = = = 0) printf (% d% n% n% d, head); for (% d, head); for // / / / / / int min (bashuma Bsm {}}} // / / / / / / / / / / / / find the smasmallest; int; flag = = 1) continue; if (smallest gt; Bsm {i}. a）最小＝1BSM {I}}。（i＝1；i＝1；k lt；9；k++ {if）（bSM{{}}}。{k}{k}==＝＝0)返回；I+++{I++{如果(bsm{i}}_______如果(最小=== =__Bsm{i{i{i}{k}} =＝＝k} =＝＝0}＝＝0}_1}{标志_{1}1}1}继续；I+++++{如果继续；如果__最低___最低_== =_Bsm＝＝Bsm{Bsm{Bsm{{Bsm{i}i}i}i}{i}{i}{i}.ccstate {k} = = = 0} k}= = 0) K l; for (k = 0; K lt; = ta; K + +) {l = 0; for (j = 0; J l)T; 9; j + + {{if (bsm1 {k}}}.Ccstate {j} === = Bsm {head}}.Ccstate {j}}} = Bsm {head}}} L + +;}}}}}}} {{int c, k, j, flag, n, a; / / / / / / / / / / / / / / / / / / / / (! 检查(bsm{bsm}}}{bsm{bsm}}}}}}}}}{{头部}}}{{{{{{头部_}}{{{{{bsm{bsm{bsm{bsm}}}}}}}}}}{{{{{{{{{{{{{{{{{{{其他返回{{{其他返回1}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}___{{{{{{{{{{{{{{{{{}.CSTATA{NXT}；BSM {头}。CcStAT{nxt}＝0；RUDUI1（BSM，BSM1，CDIR {DIR}）；和 //恢复数组以转换BSM{Head }。CcSt{{}} BSM {头}；BSM {头}{CcSt}}（＝CcStAT}（＝0）；AD！= 0（BSM {头}}！FX！＝opcdir{dir}{dir}}opcdir{dir}}canMove(现在，dir，nxt})canMove(现在，dir，dir，nxt}})canMove(现在，dir，dir，dir，nxt}}}}})canMove(现在，dir，dir，nxt，nxt，nxt，nxt，nxt，nxt{nxt，nxt{nxt{nxt{nxt{bsm{头部头部头部{头部头部头部{{头部{{{nxt}{nxt}{nxt{nxt}nxt}.nxt}.nxt}.nxt}{_sm，BSM1){rudui1(bsm，bsm，b1，b1，bsm1，CDir{dir}}}；}bsm{头}}{Cuth}}{CcSt}} = BSM {Xt}= BSM{{ }}}}{头}} ZuiHui{M}= Min（BSM1）；A= Zui啸{M}；BSM1{A}。flag=1;m++；A*算法找到进入队列头++作为扩展节点的最小步骤，否则它不加入队列rudui（bsm，bsm1，a）；if（检查（bsm{head}）。CcStand）返回1；否则返回0；}无效Shuchu（BasHua BSM {}，int i）{INTK；如果（BSM {I}）。预（＝1）返回；IF（BSM {I}）＝1）UCU（BSM，BTF {I} }（
打印n）；）（k＝0；KLT；9；k++）{if（k% 3＝＝0）PrtTf（））PrdTf（%d，BSM {i}，CcStand {k}）；}步骤++；PrtTf（；int int（）{int i，k，s；basHua bSm {n}，bSM1{n}；bSM { 0 }＝CHuHIHIVE（BSM）；（k＝0；KLT；9；k++）{if（k% 3＝＝0）PrINTF（）printf(%d，bsm{0}.ccstate{k})；}bsm1{0}=chushi.(bsm1)；i=pp(bsm，bsm1)；if(i){s=Bsm{head}.pre；Shuchu(BSM1，s)；printf(达到目标状态的总共%d步骤！，步骤+1）；} PrimTF（在深度限制下没有找到解决方案）！八位数字也使用状态空间方法，其中最突出的一点是操作集是空间移动的地方。为了简化，将操作集分成四个步骤。同时，使用A*算法根据第八位数字确定展开节点。AT不在位置，请将初始状态附加到此结束：{Write a photo description here} (http://img.blog.csdn.net/20170707070707070701701161701701702546watermark/2/text/aHR0cDovL2Jsb2Jsb2cuY3Nkbi5uZXQvcXFffMzM0NDk3OTA =/font/5a6L5L2T/font size/fontsize/400/fill/I0JBQBQKFCMA = =====/dissodissodisso/70/70/gravity/south/East! {WWrite a photo description here} (http://///imp://blog.csdg.blog.blog.blog..Net/20170701161916209watermark/2/text/aHR0cDovL2Jb2Jsb2cDovL2Jsb22cuY3Nkbi5uZXQvcvvccXfffMzMzM0NDk3OTA =/font/5a6L5L2T/fontsize/400/fill/fill/I0JBQkFCMA = =====/dissolve/dissolvelve/70/gravity/SouthEast) Running results are as follows: {Write here photo description} (http://img.csdn.net/20170170170170170170170170116183131313watermark/2 watermark/text/text/text/5a6L5L5L2T/fontsize/fontsize/400/fill/fill/I5uZXQvcXFfMzM0NDk3OTA=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/di溶胶/70/重力东南部)12345678910110111211151515151515151515151515171922222222222222222333345454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545454545456666666666666670888888889;98989898989810110110110110110110101010101010101010101010101010101010101010101010101010101010101010101011011011011011011011011011011011011011011011011313131314414141515151515151515151515151515151515151515151515151515151515151515151515151515151515151515151515151515151515116161717171811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811811911911911911911911911911921921921921901901901901901901901901901901901901901901901901901901901901901901201201201201201201201201201221221222121212122222222222222222222222222222222222222222222232323232332323232323232323232323223232324242424242424242424242424242424242424242424252525252525252526262662626262626262626262626272727272282828289292929292929292929292929292929292929292929292929292929292929292929292929292929292929292929292929292929292929 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 29 2302