[笔试] 拼多多数据分析师岗位秋招笔试题2018

-- 1. 时间粒度是小时
select 
	distinct uid 
from(
	select 
		substr(login_time,1,13),
		uid,
		count(1) as icount 
	from 
		t_login_record
	where 
		to_date(login_time) = '2018-07-01'
	group by 
		substr(login_time,1,13),
		uid 
	)t 
where 
	icount > 10 ;

-- 2. 以分钟为粒度
select distinct 
	a.uid
from(
	select 
		a.uid,
		a.login_time,
		count(b.uid) as icount
	from(
		select 
			concat(substr(login_time,1,16),'-00') as login_time,
			uid
		from 
			t_login_record
		where 
			to_date(login_time) = '2018-07-01'
		)a
	left join(
		select
			concat(substr(login_time,1,16),'-00') as login_time,,
			uid
		from 
			t_login_record
		where 
			to_date(login_time) = '2018-07-01'
		)b
	on 
		a.uid = b.uid 
	and 
		unix_timestamp(a.login_time) - unix_timestamp(b.login_time) between -3600 and -1
	group by 
		a.uid,a.login_time
	)t 
where 
	icount>10;

-- 每天注册用户总量及占所有用户比例,
select 
	a.reg_date,
	a.platform,
	a.iregcount,
	case when a.iregcount is null then 0 else a.iregcount end * 100 / b.iregcount as iregpercent
from(
	select
		to_date(reg_time) as reg_date,
		platform,
		count(distinct uid) as iregcount
	from 
		t_user  
	where
		to_date(reg_time) between '2018-01-01' and '2018-01-31'
	group by 
		to_date(reg_time),
		platform
		
	union all 
	
	select
		to_date(reg_time) as reg_date,
		'all platform' as platform,
		count(distinct uid) as iregcount
	from 
		t_user 
	where 
		to_date(reg_time) between '2018-01-01' and '2018-01-31'
	group by 
		to_date(reg_time)
	) a 
left join(
	select 
		count(distinct uid) as iregcount
	from 
		t_user  
	group by 
		platform
	) b 
on 
	1= 1;

-- 各平台用户按周同比增长

select 
	a.reg_week,
	a.platform,
	case when b.iregcount is null then null else 
		round(100 * (b.iregcount - a.iregcount) / a.iregcount ,2) as ireg_increase_precent
from (
	select 
		weekofyear(reg_time) as reg_week,
		platform,
		count(distinct uid) as iregcount
	from 
		t_user
	where 
		to_date(reg_time) between '2018-01-01' and '2018-01-31'
	group by 
		weekofyear(reg_time) as reg_week,
		platform
	) a 
left join (
	select 
		weekofyear(reg_time) as reg_week,
		platform,
		count(distinct uid) as iregcount
	from 
		t_user
	where 
		to_date(reg_time) between '2018-01-01' and '2018-01-31'
	group by 
		weekofyear(reg_time) as reg_week,
		platform
	) b 
on 
	a.platform = b.platform
and 
	a.reg_week = b.reg_week + 1
	;

select 
	uid,
	sum(case when datediff(CURRENT_DATE,to_date(ordr_time)) = 1 then goods_num else 0 end),
	sum(case when datediff(CURRENT_DATE,to_date(ordr_time)) <= 7 then goods_num else 0 end),
	sum(case when datediff(CURRENT_DATE,to_date(ordr_time)) <= 30 then goods_num else 0 end),
	sum(goods_num)
from 
	t_trade_records
where
	datediff(CURRENT_DATE,to_date(ordr_time)) <= 180
group by 
	uid