招商银行2018年秋招算法工程师岗位笔试题及AC答案

给定一个整数n，请找出阶乘末尾有n个0的所有正整数：

我的解法：

def num_of_zero(N):
    b = N
    numZero = 0
    while True:
        if b > 0:
            b = int(b / 5)
            numZero += b
        else:
            break
    return numZero

def solution(n):
    alist = []
    numZero = 0
    res = 1
    num = 1
    while numZero <= n:
        res *= num
        num += 1
        numZero = num_of_zero(num)
        if numZero == n:
            alist.append(num)
    return alist

if __name__ == '__main__':
    n = int(raw_input())
    alist = solution(n)
    print " ".join(str(i) for i in alist) 

其中num_of_zero的函数是参照另一篇博客写的：https://blog.csdn.net/gogogo_sky/article/details/75734561