【CCF 201609-3】炉石传说

版权声明: https://blog.csdn.net/leelitian3/article/details/82426558

本题并不难,只要按照题目要求模拟就好了。

大致思路

①用vector<People> player[2]代表2个玩家。int cur; //当前玩家  int wait; //等待玩家

②People是他们的英雄和随从,拥有health、attack、position三个属性

③Summon:将对应的People push_back到对应玩家即可

④attack:找到对应的两个People,改变health值。若死亡,则按要求改变其他随从的位置

⑤最后,所有随从按position排序,按题意输出即可

C++满分代码(无注释)

#include <iostream>
#include <vector>
#include <map>
#include <algorithm>
#include <cstring>
#define endl "\n"
using namespace std;

struct People
{
	int health, attack, number;
	People(int a = 0, int b = 0, int c = 0)
	{
		health = a;
		attack = b;
		number = c;
	}
};

vector<People> player[2];

int n,health,attack,pos,cur,wait;
vector<People>::iterator it;
string op;

void Summon()
{
	cin>>pos>>attack>>health;
	for(it = player[cur].begin(); it != player[cur].end(); ++it)
	{
		if(it->number != 0 && it->number >= pos)
			++(it->number);
	}
	player[cur].push_back(People(health,attack,pos));
}

void Attack()
{
	int i,j,A,B;
	cin>>A>>B;

	for(i=0; i<player[cur].size(); ++i)
		if(player[cur][i].number == A) break;
	for(j=0; j<player[wait].size(); ++j)
		if(player[wait][j].number == B) break;

	player[cur][i].health -= player[wait][j].attack;
	player[wait][j].health -= player[cur][i].attack;

	if(player[cur][i].health <= 0 && A != 0)
	{
		for(it = player[cur].begin(); it != player[cur].end(); ++it)
		{
			if(it->number != 0 && it->number > A)
				--(it->number);
		}
		player[cur].erase(player[cur].begin()+i);
	}
	if(player[wait][j].health <= 0 && B != 0)
	{
		for(it = player[wait].begin(); it != player[wait].end(); ++it)
		{
			if(it->number != 0 && it->number > B)
				--(it->number);
		}
		player[wait].erase(player[wait].begin()+j);
	}
}

void Check()
{
	if(player[0][0].health <= 0)
		cout<<-1<<endl;
	else if(player[1][0].health <= 0)
		cout<<1<<endl;
	else cout<<0<<endl;

	cout<<player[0][0].health<<endl;
	cout<<player[0].size()-1;
	for(int i=1; i<player[0].size(); ++i)
		cout<<" "<<player[0][i].health;

	cout<<endl;
	cout<<player[1][0].health<<endl;
	cout<<player[1].size()-1;
	for(int i=1; i<player[1].size(); ++i)
		cout<<" "<<player[1][i].health;
}

bool cmp(const People& a, const People& b)
{
	return a.number < b.number;
}

/*
void debug()
{
	for(int i=0; i<player[0].size(); ++i)
		cout<<player[0][i].number<<","<<player[0][i].health<<","<<player[0][i].attack<<"  ";
	cout<<endl;
	for(int i=0; i<player[1].size(); ++i)
		cout<<player[1][i].number<<","<<player[1][i].health<<","<<player[1][i].attack<<"  ";
	cout<<endl;
}
*/

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

	player[0].push_back(People(30,0,0));
	player[1].push_back(People(30,0,0));

	cin>>n;
	cur = 0, wait = 1;
	while(n--)
	{
		cin>>op;
		if(op == "summon")
			Summon();
		else if(op == "attack")
			Attack();
		else if(op == "end")
			swap(cur, wait);
		//debug();
	}

	sort(player[0].begin(), player[0].end(), cmp);
	sort(player[1].begin(), player[1].end(), cmp);
	Check();
	return 0;
}

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转载自blog.csdn.net/leelitian3/article/details/82426558