【LightOj 1265】 Island of Survival (概率)

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代码

#include <cstdio>
int T,n,m;
int main(){
    scanf("%d",&T);
    for(int tt=1;tt<=T;tt++){
        scanf("%d%d",&n,&m);
        if(n%2) printf("Case %d: 0\n",tt);
        else printf("Case %d: %lf\n",tt,(double)1/(n+1));
    }
    return 0;
}

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转载自blog.csdn.net/sunshiness_s/article/details/82619783