丑数计算

将给定个数的丑数由小到大输出

丑数（因子只包含2，3，5的数），1作为第一个丑数

思路：丑数应该是另一个丑数除以2，3，5的结果（1除外）

#include <iostream>
using namespace std;

class  Test{
        private:
                long long* pNumbers;
                int total;
                int MIN(long long number1,long long number2,long long number3)
                {
                        long long min = (number1<number2)? number1:number2;
                        min=(min<number3)?min:number3;
                        return min;
                }
        public:
                Test(int index):total(index)
                {
                        pNumbers = new long long[index];
                        pNumbers[0]=1;
                        int nextNumber=1;

                        long long* pMultiply2 = pNumbers;
                        long long* pMultiply3 = pNumbers;
                        long long* pMultiply5 = pNumbers;

                        while(nextNumber < index)
                        {
                                long long min = MIN(*pMultiply2*2,*pMultiply3*3,*pMultiply5*5);
                                pNumbers[nextNumber]=min;

                                while(*pMultiply2*2<=pNumbers[nextNumber])
                                        ++pMultiply2;
                                while(*pMultiply3*3<=pNumbers[nextNumber])
                                        ++pMultiply3;
                                while(*pMultiply5*5<=pNumbers[nextNumber])
                                        ++pMultiply5;

                                ++nextNumber;
                        }
                }

                ~Test(){

                        delete[] pNumbers;
                }

                void show()
                {
                        for(int i=0;i<total;i++)
                                cout<<pNumbers[i]<<" ";
                        cout<<endl;
                }

};

int main()
{

        Test t(1500);
        t.show();
}

运行结果：