BZOJ1026&&洛谷P2657 [SCOI2009]windy数

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代码

#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
int l,r;
int f[50][20],lim[50];
int dfs(int len,int last,bool jud)
{
	if (len<1) return 1;
	if (!jud&&f[len][last]!=-1) return f[len][last];
	int emm=(jud?lim[len]:9);int cnt=0;
	for (int i=0;i<=emm;i++)
	{
		if (abs(i-last)<2) continue;
		if (last==-10&&i==0) cnt+=dfs(len-1,last,jud&&(emm==i));
        else cnt+=dfs(len-1,i,jud&&(emm==i));
	}
	if(last>=0&&!jud) f[len][last]=cnt;
	return cnt;
}
void slove(int x,int y)
{
	int len=0;
	while (x) lim[++len]=x%10,x/=10;
	memset(f,255,sizeof(f));
	int ans=dfs(len,-10,1);
	len=0;
	while (y) lim[++len]=y%10,y/=10;
	memset(f,255,sizeof(f));
	int que=dfs(len,-10,1);
	cout<<ans-que;
	return ;
}
signed main()
{
	cin>>l>>r;slove(r,l-1);
	return 0;
}

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转载自blog.csdn.net/ACerAndAKer/article/details/81334839