和为s的两个数字+为s的连续正数序列

bool FindNumbersWithSum(int data[], int length, int sum, 
                        int* num1, int* num2)
{
    bool found = false;
    if(length < 1 || num1 == nullptr || num2 == nullptr)
        return found;

    int ahead = length - 1;
    int behind = 0;

    while(ahead > behind)
    {
        long long curSum = data[ahead] + data[behind];

        if(curSum == sum)
        {
            *num1 = data[behind];
            *num2 = data[ahead];
            found = true;
            break;
        }
        else if(curSum > sum)
            ahead --;
        else
            behind ++;
    }

    return found;
}

void FindContinuousSequence(int sum)
{
    if(sum < 3)
        return;

    int small = 1; 
    int big = 2;
    int middle = (1 + sum) / 2;
    int curSum = small + big;

    while(small < middle)
    {
        if(curSum == sum)
            PrintContinuousSequence(small, big);

        while(curSum > sum && small < middle)
        {
            curSum -= small;
            small ++;

            if(curSum == sum)
                PrintContinuousSequence(small, big);
        }

        big ++;
        curSum += big;
    }
}