hduoj_1232(最大连续子串和)

再写一遍,加深印象。

#include <stdio.h>

int main()
{
	int n;
	int i;
	int k[10000];
	int flag;
	while (EOF != scanf("%d", &n) && n)
	{
		int nowLeft, nowRight, left, right, nowValue, max;

		nowLeft = nowRight = left = right = 1;

		flag = 0;

		nowValue = 0;
		max = -1;
		for (i = 1; i <= n; i++)
		{
			scanf("%d", &k[i]);

			if (k[i] >= 0)
				flag = 1;

			nowValue += k[i];

			nowRight = i;

			if (max < nowValue)
			{
				max = nowValue;
				left = nowLeft;
				right = nowRight;
			}
			if (nowValue < 0)
			{
				nowValue = 0;
				nowLeft = nowRight = i + 1;
			}
		}

		if (!flag)
		{
			left = 1;
			right = n;
			max = 0;
		}

		printf("%d %d %d\n", max, k[left], k[right]);
	}
	return 0;
}

猜你喜欢

转载自blog.csdn.net/qq_32862515/article/details/80710248
今日推荐