\[ \lim_{n \to \infty} (1+\frac{1}{n})^{n} = e\] $$\lim_{x \to 0} \frac{\sin x}{x} = 1 $$
\( e^{\pi i} + 1 = 0\) $\alpha + \beta = 0$
\( e^{\pi i} + 1 = 0\) $\alpha + \beta = 0$
\( e^{\pi i} + 1 = 0\) $\alpha + \beta = 0$
\[\sum_{k=1}^n k = \frac{n(n+1)}{2}\]