【数学建模】基于AR预测

一.概述

时间有限,先将代码展示,有时间再写详解

二.代码总结

clear;
%--------------------------------油价序列零均值化后的数据如下----------------------------------------%:
P=[ 19.5900   14.9100   15.7400   15.4000   13.0600   19.0700   15.2800   15.8200   12.7700   12.0500...  
    11.6900   13.8500   13.8500   10.0700    9.1700   10.7900   13.4400   21.1700   18.6400   13.2100...  
    15.5400   21.9400   23.1100   18.6400   14.9400   16.9000   15.4600   11.1500   13.1300   12.4800...  
    12.9500   12.5900   10.5800   10.5800   12.3900   15.5300   13.0600   10.2200   16.3300   19.7200...
    21.3100   18.8400   24.8400   15.6700   15.5700   12.7300   13.5600   15.5400   17.2200   12.1400...
    11.0700   12.0200   11.5500    6.9200   10.3300   8.3800    12.1100   11.4600   12.7500   13.3200...
    13.0000   11.9000   11.7900   12.5500   11.8400   11.2500   11.1500   10.9900   11.7000   14.0100...
    17.5100   17.2700   16.9000   15.7900   15.4500   6.2400    16.7100   16.7700   16.6400   17.8000...
    16.8700   16.1300   15.7600   15.6600   15.5400   15.3000   15.0500   14.6900   14.3900   14.1800...
    13.70     13.66     13.27     13.56     13.14     14.19 ];
F=[ 19.5900   14.9100   15.7400   15.4000   13.0600   19.0700   15.2800   15.8200   12.7700   12.0500...  
    11.6900   13.8500   13.8500   10.0700    9.1700   10.7900   13.4400   21.1700   18.6400   13.2100...
    15.5400   21.9400   23.1100   18.6400   14.9400   16.9000   15.4600   11.1500   13.1300   12.4800...
    12.9500   12.5900   10.5800   10.5800   12.3900   15.5300   13.0600   10.2200   16.3300   19.7200...
    21.3100   18.8400   24.8400   15.6700   15.5700   12.7300   13.5600   15.5400   17.2200   12.1400...
    11.0700   12.0200   11.5500    6.9200   10.3300   8.3800    12.1100   11.4600   12.7500   13.3200...
    13.0000   11.9000   11.7900   12.5500   11.8400   11.2500   11.1500   10.9900   11.7000   14.0100...
    17.5100   17.2700   16.9000   15.7900   15.4500   6.2400    16.7100   16.7700   16.6400   17.8000...
    16.8700   16.1300   15.7600   15.6600   15.5400   15.3000   15.0500   14.6900   14.3900   14.180];

%----------------------由于时间序列有不平稳趋势,进行两次差分运算,消除趋势性----------------------%
for i=2:96
    Yt(i)=P(i)-P(i-1);
end
for i=3:96
    L(i)=Yt(i)-Yt(i-1);
end
figure;
L=L(3:96);
Y=L(1:88);
plot(P);
title('原数据序列图');
hold on;
pause 
plot(Y,'r');
title('两次差分后的序列图和原数对比图');
pause  
%--------------------------------------对数据标准化处理----------------------------------------------%
Ux=sum(Y)/88                           % 求序列均值
yt=Y-Ux;
b=0;
for i=1:88
   b=yt(i)^2/88+b;
end
v=sqrt(b)                              % 求序列方差
Y=(Y-Ux)/v;                             % 标准化处理公式
f=F(1:88);
t=1:88;
figure;
plot(t,f,t,Y,'r')
title('原始数据和标准化处理后对比图');
xlabel('时间t'),ylabel('油价y');
legend('原始数据 F ','标准化后数据Y ');
pause  
%--------------------------------------对数据标准化处理----------------------------------------------%


%------------------------检验预处理后的数据是否符合AR建模要求,计算自相关和偏相关系数---------------%
   %---------------------------------------计算自相关系数-----------------------------------%
R0=0;
for i=1:88 
     R0=Y(i)^2/88+R0;
end
R0
for k=1:20
    R(k)=0;
   for i=k+1:88
      R(k)=Y(i)*Y(i-k)/88+R(k);
   end
   R                        %自协方差函数R   
end
x=R/R0                      %自相关系数x
figure;
plot(x)
title('自相关系数分析图');
pause  
%-----------------------------------计算自相关系数-------------------------------------%

   %-----------------------解Y-W方程,其系数矩阵是Toepli矩阵。求得偏相关函数X-----------------------%
X1=x(1);
X11=x(1);
B=[x(1) x(2)]';
x2=[1 x(1)];
A=toeplitz(x2);                      
X2=A\B
X22=X2(2)

B=[x(1) x(2) x(3)]';
x3=[1 x(1) x(2)];
A=toeplitz(x3);                      
X3=A\B
X33=X3(3)

B=[x(1) x(2) x(3) x(4)]';
x4=[1 x(1) x(2) x(3)];
A=toeplitz(x4);                      
X4=A\B
X44=X4(4)

B=[x(1) x(2) x(3) x(4) x(5)]';
x5=[1 x(1) x(2) x(3) x(4)];
A=toeplitz(x5);                      
X5=A\B
X55=X5(5)

B=[x(1) x(2) x(3) x(4) x(5) x(6)]';
x6=[1 x(1) x(2) x(3) x(4) x(5)];
A=toeplitz(x6);                      
X6=A\B
X66=X6(6)

B=[x(1) x(2) x(3) x(4) x(5) x(6) x(7)]';
x7=[1 x(1) x(2) x(3) x(4) x(5) x(6)];
A=toeplitz(x7);                      
X7=A\B
X77=X7(7)

B=[x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8)]';
x8=[1 x(1) x(2) x(3) x(4) x(5) x(6) x(7)];
A=toeplitz(x8);                      
X8=A\B
X88=X8(8)

B=[x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9)]';
x9=[1 x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8)];
A=toeplitz(x9);                      
X9=A\B
X99=X9(9)

B=[x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9) x(10)]';
x10=[1 x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9)];
A=toeplitz(x10);                      
X10=A\B   
X1010=X10(10)
     
B=[x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9) x(10) x(11)]';
x11=[1 x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9) x(10)];
A=toeplitz(x11);                      
X101=A\B   
X1111=X101(11)

B=[x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9) x(10) x(11) x(12)]';
x12=[1 x(1) x(2) x(3) x(4) x(5) x(6) x(7) x(8) x(9) x(10) x(11)];
A=toeplitz(x12);                      
X12=A\B   
X1212=X12(12)

X=[X11 X22 X33 X44 X55 X66 X77 X88 X99 X1010  X1111 X1212] 
%-----------------------------------解Y-W方程,得偏相关函数X-------------------------------------%
figure; 
plot(X);
title('偏相关函数图');
pause 

%-----根据偏相关函数截尾性,初判模型阶次为5。用最小二乘法估计参数,计算10阶以内的模型残差方差和AIC值,应用AIC准则为模型定阶------%
   S=[R0 R(1) R(2) R(3) R(4)];
   G=toeplitz(S);
   W=inv(G)*[R(1:5)]'                      % 参数W(i) 与X5相同
   
   K=0;                              
   for t=6:88
       r=0; 
       for i=1:5
           r=W(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K;                                                     
    end
    U(5)=K/(88-5)                        % 5阶模型残差方差 0.4420
                                                       
K=0;T=X1;
for t=2:88
    at=Y(t)-T(1)*Y(t-1);
    K=(at)^2+K; 
end                        
  U(1)=K/(89-1)                         % 1阶模型残差方差0.6954           
  
   K=0;T=X2;
   for t=3:88                                                      
       r=0; 
       for i=1:2
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(2)=K/(88-2)                     % 2阶模型残差方差 0.6264  
    
   K=0;T=X3;
   for t=4:88
       r=0; 
       for i=1:3
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(3)=K/(88-3)                      % 3阶模型残差方差 0.5327
    
    K=0;T=X4;
    for t=5:88
       r=0; 
       for i=1:4
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(4)=K/(88-4)                     % 4阶模型残差方差  0.4751 
    
    K=0;T=X6;
    for t=7:88
       r=0; 
       for i=1:6
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(6)=K/(88-6)                     % 6阶模型残差方差 0.4365 
    
    K=0;T=X7;
    for t=8:88                                            
       r=0; 
       for i=1:7
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(7)=K/(88-7)                     % 7阶模型残差方差 0.4331
    
    K=0;T=X8;
    for t=9:88
       r=0; 
       for i=1:8
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(8)=K/(88-8)                     % 8阶模型残差方差0.4310 
    
    K=0;T=X9;
    for t=10:88
       r=0; 
       for i=1:9
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(9)=K/(88-9)                     %9阶模型残差方差 0.4297
    
    K=0;T=X10;
    for t=11:88
       r=0; 
       for i=1:10
           r=T(i)*Y(t-i)+r;
       end
       at= Y(t)-r;
       K=(at)^2+K; 
    end
    U(10)=K/(88-10)                   % 10阶模型残差方差 0.4317 
  
    U=10*U
    for i=1:10
     AIC2(i)=88*log(U(i))+2*(i)        % AIC值分别为:172.6632  165.4660  153.2087  145.1442  140.7898  141.6824  142.9944  144.5601  146.3067  148.7036
    end
%-----------------取使AIC值为最小值的阶次,判断模型阶次为5。用最小二乘法估计参数--------------------%

 
%------------------检验{at}是否为白噪声。求{at}的自相关系数,看其是否趋近于零-----------------------%
   C=0;K=0;
 for t=7:88
     at=Y(t)-W(1)*Y(t-1)-W(2)*Y(t-2)-W(3)*Y(t-3)-W(4)*Y(t-4)-W(5)*Y(t-5)+Y(6)-W(1)*Y(5)-W(2)*Y(4)-W(3)*Y(3)-W(4)*Y(2)-W(5)*Y(1);
     at1=Y(t-1)-W(1)*Y(t-2)-W(2)*Y(t-3)-W(3)*Y(t-4)-W(4)*Y(t-5)-W(5)*Y(t-6);
     C=at*at1+C;
     K=(at)^2+K; 
end
 p=C/K              %若p接近于零,则{at}可看作是白噪声                 
 %--------------------------------{at}的自相关系数,趋近于零,模型适用--------------------------------%
 
 
 %------------AR(5)模型方程为------------------------------------------------------------------------%
  % X(t)=W(1)*X(t-1)-W(2)*X(t-2)-W(3)*X(t-3)-W(4)*X(t-4)-W(5)*X(t-5)+at     (at=0.4420)
 
 
%------------------------------------------后六年的数据 进行预测和效果检验----------------------------------------------%
 
%-----------------------------单步预测  预测当前时刻后的六个数据----------------------------------%
 XT=[L(84:94)]; 
 for t=6:11
    m(t)=0;
    for i=1:5
       m(t)=W(i)*XT(t-i)+m(t);  
    end
 end

 m=m(6:11);
  
 %-------------预测值进行反处理---------------%
  m(1)=Yt(90)+m(1);            %一次反差分
  z1(1)=P(90)+m(1);            %二次反差分
  m(2)=Yt(91)+m(2);
  z1(2)=P(91)+m(2);  
   m(3)=Yt(92)+m(3);
  z1(3)=P(92)+m(3); 
   m(4)=Yt(93)+m(4);
  z1(4)=P(93)+m(4); 
   m(5)=Yt(94)+m(5);
  z1(5)=P(94)+m(5); 
   m(6)=Yt(95)+m(6);
  z1(6)=P(95)+m(6); 
  z1                                               % 单步预测的向后6个预测值:z1= 13.9423   13.4101   13.3588   12.9856   13.2594   12.9552

 %---------------------------绘制数据模型逼近曲线-----------------------------------%
 for  t=6:88
    r=0; 
    for i=1:5
       r=W(i)*Y(t-i)+r;
    end
    at= Y(t)-r;    
end 

figure;
for t=6:88
   y(t)=0;
   for i=1:5
      y(t)=W(i)*Y(t-i)+y(t);  
   end
   y(t)=y(t)+at;
   y(t)=Yt(t+1)-y(t);
   y(t)=P(t+1)-y(t);
end
plot(y,'r-*');                    % 样本数据模型逼近曲线
hold on;
plot(91:96,z1,'r-*'); 
hold on;
plot(P,'--');                     % 原样本曲线
title('AR(5)模型样本逼近预测曲线');
pause  

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转载自blog.csdn.net/m0_65157892/article/details/129460515