C语言写游戏——扫雷

实现效果比较简陋,如图:

 

写游戏需要不同的文件构成,首先看一下资源管理器清楚框架结构:

在test.c文件里编写整个游戏的运行逻辑,具体代码:

#define _CRT_SECURE_NO_WARNINGS 1
#include "game.h"
//测试游戏
void menu()
{
	printf("*******************************\n");
	printf("*********    1.play    ********\n");
	printf("*********    0.exit    ********\n");
	printf("*******************************\n");
}

void game()
{
	//雷的信息存储
	//1.布置好的雷的信息     //11*11真实的棋盘
	char mine[ROWS][COLS] = { 0 };//11*11
	//2.排查出的雷的信息    //11*11真实的棋盘
	char show[ROWS][COLS] = { 0 };
	//初始化       //11*11真实的棋盘
	InitBoard(mine, ROWS, COLS,'0');
	InitBoard(show, ROWS, COLS,'*');
	//打印棋盘
	//DisplayBoard(mine, ROW, COL);//打印9*9的棋盘
	DisplayBoard(show, ROW, COL);
	//布置雷
	SetMine(mine, ROW, COL);
	//DisplayBoard(mine, ROW, COL);
	//扫雷
	FindMine(mine, show, ROW, COL);
}

void test()
{
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("请选择:");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏\n");
			break;
		default:
			printf("选择错误,请重新输入\n");
			break;
		}
	} while (input);
}

int main()
{
	test();
	return 0;
}

各个模块跨文件调用的话需要在头文件里声明,即game.h文件内:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROW 9
#define COL 9
#define ROWS ROW+2 //创建9*9的棋盘为了保证角落的有效性需要创建11*11
#define COLS COL+2
#define EASY_COUNT 10

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

扫雷游戏最核心的是游戏模块的实现,在game.c内编写

#define _CRT_SECURE_NO_WARNINGS 1
#include "game.h"
//游戏部分函数功能实现
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
	int j = 0;
	int i = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}

void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i <= col; i++)//打印列号
	{
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <= row; i++)//打印棋盘
	{
		printf("%d ", i);//打印行号
		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("\n");
	}
}

void SetMine(char board[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % row + 1;//1-9
		int y = rand() % col + 1;
		if (board[x][y] == '0')
		{
			board[x][y] = '1';
			count--;
		}
	}
}

//'0' - '0'=0  
//'1' - '0'=1 //字符1减字符零等于数字1
//'3' - '0'=3
int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
		return mine[x - 1][y] +
		mine[x - 1][y - 1] +
		mine[x][y - 1] +
		mine[x + 1][y - 1] +
		mine[x + 1][y] +
		mine[x + 1][y + 1] +
		mine[x][y + 1] +
		mine[x - 1][y + 1] - 8 * '0';
}

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win < row*col - EASY_COUNT)//假如设置10个雷9*9-10=71有71处不是雷
	{
		printf("请输入排雷的坐标:");
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row&&y >= 1 && y <= col)
		{
			//坐标合法
			//1.踩雷
			if (mine[x][y] == '1')
			{
				printf("很遗憾,你被炸死了\n");
				DisplayBoard(mine, row, col);
				break;
			}
			else//不是雷
			{
				//计算x,y坐标周围有几个雷
				int count = get_mine_count(mine, x, y);
				show[x][y] = count + '0';
				DisplayBoard(show, row, col);
				win++;
			}
		}
		else
		{
			printf("输入坐标非法,请重新输入!\n");
		}
	}
	if (win == row*col - EASY_COUNT)
	{
		printf("恭喜你排雷成功\n");
		DisplayBoard(mine, row, col);
	}
}

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转载自blog.csdn.net/qq_44928278/article/details/122718986