二、数据查询语言(五)

MySQL


一、初识数据库
二、数据查询语言(一)
二、数据查询语言(二)
二、数据查询语言(三)
二、数据查询语言(四)

数据查询语言包括: 基础查询 条件查询 排序查询 分组查询 连接查询 子查询 分页查询 联合查询

前言


提示:以下是本篇文章正文内容,下面案例可供参考
且所用数据表为:可自行下载

子查询

含义:
出现在其他语句中的select语句,称为子查询或内查询
外部的查询语句,称为主查询或外查询
分类:
按子查询出现的位置:
select后面
仅仅支持标量子查询
from后面
支持表子查询
where或having后面 ❤
标量子查询 √
列子查询 √
行子查询
exists后面(相关子查询)

按结果集的行列数不同:
	标量子查询(结果集只有一行一列)
	列子查询(结果集为一列多行)
	行子查询(结果集有一行多列)
	表子查询(结果集一般为多行多列)

where或having后面 ❤

1、标量子查询 (单行子查询) √
	2、列子查询   (多行子查询) √
	3、行子查询	(多行多列)
	
特点:
	①子查询放在小括号内
	②子查询一般放在条件的右侧
	③标量子查询,一般搭配着单行操作符使用
	> < >= <= <>
	
	列子查询:一般搭配着多行操作符使用
	in 、any/some、all
	
	④子查询的执行优先于主查询执行,主查询的条件用到了子查询的结果

标量子查询

案例1:谁的工资比Abel高?

#①先查询abel的工作
SELECT salary
FROM employees
WHERE last_name='Abel';

#②查询员工的信息,满足salary>①结果
SELECT *
FROM employees
WHERE salary>(
	SELECT salary
	FROM employees
	WHERE last_name='Abel'
);

案例2:返回job_id与141号员工相同,salary比143号员工多的员工姓名,job_id和工资

#①查询141号员工的job_id
SELECT job_id
FROM employees
WHERE employee_id=141;

#②查询143号员工的salary
SELECT salary
FROM employees
WHERE employee_id=143;

#③查询员工的姓名,job_id和工资,要求job_id=①并且salary>②
SELECT last_name,job_id,salary
FROM employees	
WHERE job_id=(
	SELECT job_id
	FROM employees
	WHERE employee_id=141
) AND salary>(
	SELECT salary
	FROM employees
	WHERE employee_id=143);

案例3:返回公司工资最少的员工的last_name,job_id,salary

#①查询工资最少的员工
SELECT MIN(salary)
FROM employees

#②查询last_name,job_id,salary,且工资最少
SELECT last_name,job_id,salary
FROM employees
WHERE salary=(
	SELECT MIN(salary)
	FROM employees);	

案例4:查询最低工资大于50号部门的最低工资和部门id和其最低工资

#①查询50号部门的最低工资
SELECT MIN(salary)
FROM employees
WHERE department_id=50;

#②查询每个部门的最低工资
SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id

#③ 在②基础上筛选,满足min(salary)>①
SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
	SELECT MIN(salary)
	FROM employees
	WHERE department_id=50
);

非法使用标量子查询

SELECT MIN(salary),department_id
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
	SELECT MIN(salary)
	FROM employees
	WHERE department_id=50
);

列子查询(多行子查询)

案例1:返回location_id是1400或1700的部门中的所有员工姓名

#①查询location_id是14001700的部门编号
SELECT department_id
FROM departments
WHERE location_id IN(1400,1700);
#查询员工姓名,要求部门号是①列表中的某一个
SELECT last_name
FROM employees
WHERE department_id IN(
	SELECT department_id
	FROM departments
	WHERE location_id IN(1400,1700)
);

案例2:返回其它工种中比job_id为‘IT_PROG’工种任一工资低员工号、姓名、job_id以及salary

#①查询job_id为’IT_PROG'的任一工资
SELECT DISTINCT salary
FROM employees
WHERE job_id="IT_PROG"
#②查询员工号、姓名、job_id以及salary,salary>①中的任意一个
SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<ANY(
	SELECT DISTINCT salary
	FROM employees
	WHERE job_id="IT_PROG"
)AND job_id<>'IT_PROG';

#或
SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<(
	SELECT MAX(salary)
	FROM employees
	WHERE job_id="IT_PROG"
)AND job_id<>'IT_PROG';

案例3:返回其它工种中比job_id为‘IT_PROG’工种所有工资都低员工号、姓名、job_id以及salary

SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary <ALL(
	SELECT DISTINCT salary
	FROM employees
	WHERE job_id='IT_PROG'
)AND job_id<>'IT_PROG';
#或	
SELECT last_name,employee_id,job_id,salary
FROM employees
WHERE salary<(
	SELECT MIN(salary)
	FROM employees
	WHERE job_id="IT_PROG"
)AND job_id<>'IT_PROG';

行子查询(结果集一行或多行多列)

案例:查询员工编号最小并且工资最高的员工信息

USE myemployees;
SELECT *
FROM employees	
WHERE employee_id=(
	SELECT MIN(employee_id)
	FROM employees
)AND salary=(
	SELECT MAX(salary)
	FROM employees
);

行子查询做

SELECT  *
FROM employees
WHERE (employee_id,salary)=(
	SELECT MIN(employee_id),MAX(salary)
	FROM employees);

二、select后面

仅仅支持标量子查询

案例:查询每个部门的员工个数

SELECT d.*,(

	SELECT COUNT(*)
	FROM employees e
	WHERE e.department_id=d.`department_id`
) 个数
FROM departments d;

案例:查询员工号=102的部门名

SELECT(
	SELECT department_name
	FROM departments d
	INNER JOIN employees e
	ON d.`department_id`=e.`department_id`
	WHERE e.`employee_id`=102) 部门名;

三、from后面

案例:查询每个部门的平均工资的工资等级

#①查询每个部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id;

SELECT * FROM job_grades;

#②连接①的结果集和job_grades表,筛选条件平均工资between lowest_sal and highest_sal

SELECT ag_dep.*,g.`grade_level`
FROM (
	SELECT AVG(salary) ag,department_id
	FROM employees
	GROUP BY department_id
) ag_dep
INNER JOIN job_grades g
ON ag_dep.ag BETWEEN lowest_sal AND highest_sal;

四、exists后面(相关子查询)

/*
语法:
exists(完整的查询语句)
结果:1或0
*/

#案例1:查询有员工的部门名

#使用in
SELECT department_name
FROM departments d
WHERE d.`department_id` IN(
		SELECT department_id
		FROM employees
		);
#使用exists
SELECT department_name
FROM departments d
WHERE EXISTS(
	SELECT *
	FROM employees e
	WHERE d.`department_id`=e.`department_id`
);

案例2:查询没有女朋友的男神信息
#in
USE girls;

SELECT bo.*
FROM boys bo
WHERE bo.id NOT IN(
	SELECT boyfriend_id
	FROM beauty 
);

SELECT bo.*
FROM boys bo
WHERE NOT EXISTS(
	SELECT boyfriend_id
	FROM beauty b
	WHERE bo.`id`=b.`boyfriend_id`
	);

总结

期待大家和我交流,留言或者私信,一起学习,一起进步!

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转载自blog.csdn.net/CltCj/article/details/121688846