动态规划 NOI 1481:Maximum sum——顺着倒着各求一次最大连续子序列和

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Given a set of n integers: A={a1, a2,..., an}, we define a function d(A) as below:

                     t1     t2 
d(A) = max{ ∑ai + ∑aj | 1 <= s1 <= t1 < s2 <= t2 <= n }
i=s1 j=s2

#include<iostream>
#include<algorithm>
#include<string.h>
using namespace std;
int a[50001],dpleft[50001],lmax[50001],dpright[50001],rmax[50001];
int main()
{
	int times,n,i,ans;
	cin>>times;
	while(times--)
	{
		memset(dpleft,0,sizeof(dpleft));
		memset(lmax,0,sizeof(lmax));
		memset(dpright,0,sizeof(dpright));
		memset(rmax,0,sizeof(rmax));
		cin>>n;
		for (i=1;i<=n;i++)
			cin>>a[i];
		dpleft[1]=a[1];lmax[1]=a[1];
		for (i=2;i<=n;i++)
		{
			dpleft[i]=max(dpleft[i-1]+a[i],a[i]);
			lmax[i]=max(lmax[i-1],dpleft[i]);
		}
		dpright[n]=a[n];rmax[n]=a[n];
		for (i=n-1;i>=0;i--)
		{
			dpright[i]=max(dpright[i+1]+a[i],a[i]);
			rmax[i]=max(rmax[i+1],dpright[i]);
		}
		ans=lmax[1]+rmax[2];
		for (i=2;i<=n-1;i++)
			ans=max(ans,lmax[i]+rmax[i+1]);
		cout<<ans<<endl;
	}
	return 0;
}

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转载自blog.csdn.net/always_ease/article/details/80512031