题目描述
代码
class Solution {
int m, n, k;
boolean[][] visited;
public int movingCount(int m, int n, int k) {
this.m = m; this.n = n; this.k = k;
this.visited = new boolean[m][n];
return dfs(0, 0, 0, 0);
}
public int dfs(int i, int j, int si, int sj) {
if(i >= m || j >= n || k < si + sj || visited[i][j]) return 0;
visited[i][j] = true;
return 1 + dfs(i + 1, j, (i + 1) % 10 != 0 ? si + 1 : si - 8, sj)
+ dfs(i, j + 1, si, (j + 1) % 10 != 0 ? sj + 1 : sj - 8);
}
}