Leetcode 22. 括号生成 (括号匹配,dfs)

22. 括号生成

数字 n 代表生成括号的对数,请你设计一个函数,用于能够生成所有可能的并且 有效的 括号组合。

示例:

输入:n = 3
输出:[
       "((()))",
       "(()())",
       "(())()",
       "()(())",
       "()()()"
     ]
class Solution {
    List<String> ans=new ArrayList<>();
    public List<String> generateParenthesis(int n) {
        dfs(n,n,"");
        return ans;

    }
    public void dfs(int left,int right,String tep)
    {
        //System.out.println(left+" "+right);
        if(left==0&&right==0)
        {
            ans.add(tep);
            return ;
        }
        if(left>0)dfs(left-1,right,tep+"(");
        if(right>left)dfs(left,right-1,tep+")");
    }
}

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转载自blog.csdn.net/weixin_43798170/article/details/105426439