#include<stdio.h>
#include<iostream>
#include<cmath>
#include<math.h>
#include<string>
#include<string.h>
#include<algorithm>
#include<stack>
#include<queue>
#include<vector>
#include<map>
#define ms0(a) memset(a,0,sizeof(a))
#define ll long long
#define ull unsigned long long
#define INF0x3f3f3f3f
const int dx[] ={-1,1,0,0,-1,-1,1,1};
const int dy[] = {0,0,-1,1,-1,1,-1,1};
using namespace std;
int largeNumberDiv(char* s,int p)
{
int len = (int)strlen(s);
int sum=0;
for(int i=0;i<len;i++)
{
sum = sum*10 +s[i]-'0';
sum%=p;
}
return sum%p;
}
int T[]={0,1,0};
char a[10005],b[10005];
int main(){
int t;
cin>>t;
while (t--)
{
ms0(a);ms0(b);
scanf("%s%s",a,b);
printf("%d\n",(T[largeNumberDiv(b, 3)]-T[(largeNumberDiv(a, 3)+2)%3]+2)%2);
}
return 0;
}
ZOJ-4108Fibonacci in the Pocket——斐波那契+周期性+大整数取模+前缀和
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转载自blog.csdn.net/qq_44846324/article/details/104896460
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