Implement int sqrt(int x).
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4
Output: 2
Example 2:
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842…, and since
the decimal part is truncated, 2 is returned.
func mySqrt(x int) int {
l := 0
r := x + 1
for l < r {
mid := l + (r-l)/2
curr := mid * mid
if curr == x {
return mid
} else if curr > x {
r = mid
} else {
l = mid + 1
}
}
return l - 1
}